The hydrolysiis of gliadin from rye / by Thomas B. Osborne and S.H. Clapp.

  • Thomas Burr Osborne
Date:
[1908]
Catalogue details

Licence: In copyright

Credit: The hydrolysiis of gliadin from rye / by Thomas B. Osborne and S.H. Clapp. Source: Wellcome Collection.

Provider: This material has been provided by The Royal College of Surgeons of England. The original may be consulted at The Royal College of Surgeons of England.

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    The large quantity of proline contained in Fraction II was worked up conjointly with that from Fraction III. No glycocoll could be brought to separation in this fraction as the ethyl ester hydrochloride. Fraction ill.—The yield of leucine was 11.71 gm. The substance decomposed at about 298° and gave the following analysis: Carbon and hydrogen, 0.1755 gm. subst. gave 0.3524 gm. C02 and 0.1575 gm. H20. Calculated for CGH1302N = C 54.96 ; H 9.92 per cent. Found . . . . =C 54.76; H 9.97 “ “ The proline from Fractions II and III, when freed as completely as possible from substances insoluble in absolute alcohol and dried to constancy over sulphuric acid, weighed 34.67 gm. By redissolv- ing in absolute alcohol the substance separated in the characteristic prisms melting at about 206°. Carbon and hydrogen, 0.1760 gm. subst. gave 0.3348 gm. C02 and 0.1307 gm. H20. Calculated for C5H902N = C 52.18 ; H 7.83 per cent. Found .... =C 51.88; H 8.24 “ “ For identification the substance was converted to the copper salt and the lsevo separated from the racemized with absolute alcohol in the usual way. The racemic copper salt crystallized from water in the character- istic plates containing two molecules of water-of-crystallization. Water, 0.1365 gm. subst. (air dry) lost 0.0146 gm. H20 at no°. Calculated for C10H16O4N2Cu • 2 H20 = FLO 10.99 per cent. Found = H20 xo.86 « Copper, 0.1177 gm. subst. dried at no°, gave 0.0318 gm. CuO. Calculated for C10H16O4N2Cu = Cu 21.81 per cent. Found = Cu 21.59 “ “ The lasvo proline was converted to the characteristic phenyl- hydantoine. The melting-point was 1420. Carbon and hydrogen, 0.2716 gm. subst. gave 0.6604 gm. C02 and 0.1401 gm. H20. Calculated for C12H1202N2 = C 66.67 > H 5.57 per cent. Found .... = C 66.31; H 5.72 “ “